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36x^2+36x-91=0
a = 36; b = 36; c = -91;
Δ = b2-4ac
Δ = 362-4·36·(-91)
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{14400}=120$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-120}{2*36}=\frac{-156}{72} =-2+1/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+120}{2*36}=\frac{84}{72} =1+1/6 $
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